Question

A ball is thrown straight up into the air, with an initial speed of 18.2 m/. How far has it gone after 1.00 s?

Answer 1

The distance that the ball was able to travel at a given time is calculated through the equation,

    d = Vot + (1/2)(g)(t²)

Then, we substitute the known values from the given above,

   d = (-18.2 m/s)(1 s) + 0.5(-9.8 m/s²)(1 s)²
     d= -23.1 m

Thus, the distance traveled by the ball after an hour is equal to 23.1 m

ANSWER: 23.1 m

Answer 2

Answer:  13.3 m

I got it right on Acellus