Respuesta :
Here's the method on the first one (36)
The ratio is [tex]\frac{72}{126}=\frac{36}{63}=\frac{12}{21}=\frac{4}{7}[/tex], hence if we call [tex]x[/tex]the number below [tex]36[/tex], we will have [tex]\frac{36}x=\frac{72}{126}=\frac{4}7[/tex] hence [tex]x=\frac{36\cdot7}4=63[/tex]
I_72__I_36_I_24_I_12_I
I_126_I_63_I_42_I_21_I
The ratio is [tex]\frac{72}{126}=\frac{36}{63}=\frac{12}{21}=\frac{4}{7}[/tex], hence if we call [tex]x[/tex]the number below [tex]36[/tex], we will have [tex]\frac{36}x=\frac{72}{126}=\frac{4}7[/tex] hence [tex]x=\frac{36\cdot7}4=63[/tex]
I_72__I_36_I_24_I_12_I
I_126_I_63_I_42_I_21_I
[tex]\sf\frac{72}{126}=\frac{36}{x}\\Cross~multiply\\72x=126(36)\\Solve~for~x\\x=63[/tex]
[tex]\sf\frac{72}{126}=\frac{24}{y}\\Cross~multiply\\72y=126(24)\\Solve~for~y\\y=42[/tex]
[tex]\sf\frac{72}{126}=\frac{12}{z}\\Cross~multiply\\72z=126(12)\\Solve~for~z\\z=21[/tex]
And three more equivalent ratios are filled in the table:
___________________ _____________
I_72__I_36_I_24_I_12_I I_4_I_8__I_16_I
I_126_I_63_I_42_I_21_I I_7_I_14_I_28_I
I hope that helps :)
[tex]\sf\frac{72}{126}=\frac{24}{y}\\Cross~multiply\\72y=126(24)\\Solve~for~y\\y=42[/tex]
[tex]\sf\frac{72}{126}=\frac{12}{z}\\Cross~multiply\\72z=126(12)\\Solve~for~z\\z=21[/tex]
And three more equivalent ratios are filled in the table:
___________________ _____________
I_72__I_36_I_24_I_12_I I_4_I_8__I_16_I
I_126_I_63_I_42_I_21_I I_7_I_14_I_28_I
I hope that helps :)