Respuesta :
Let our basis for answering this item be 1 mol of the given substance. Then, we calculate for the equivalent mass by multiplying the number of moles with the molar mass.
mass = (102.13 g/mol)(1 mol) = 102.13 g of substance
Then, we calculate for the amount of sulfur and fluorine each using the percentage given.
sulfur = (0.6279)(102.13 g) = 64.13 g of sulfur
fluorine = (1 - 0.6279)(102.13 g) = 38 g of fluorine
Then, calculate for the number of moles of the sulfur and fluorine by dividing the calculated mass by the molar mass of each.
moles of sulfur = (64.13 g)(1 mol/32 g) = 2 mols suflur
moles of fluorine = (38 g)(1 mol/19 g) = 2 mols fluorine
The molecular formula of the substance is S₂F₂.
ANSWER: S₂F₂
mass = (102.13 g/mol)(1 mol) = 102.13 g of substance
Then, we calculate for the amount of sulfur and fluorine each using the percentage given.
sulfur = (0.6279)(102.13 g) = 64.13 g of sulfur
fluorine = (1 - 0.6279)(102.13 g) = 38 g of fluorine
Then, calculate for the number of moles of the sulfur and fluorine by dividing the calculated mass by the molar mass of each.
moles of sulfur = (64.13 g)(1 mol/32 g) = 2 mols suflur
moles of fluorine = (38 g)(1 mol/19 g) = 2 mols fluorine
The molecular formula of the substance is S₂F₂.
ANSWER: S₂F₂
The molecular formula of the compound of sulfur and fluorine is [tex]\boxed{{{\text{S}}_2}{{\text{F}}_2}}[/tex].
Further Explanation:
Empirical formula:
It is atom’s simplest positive integer ratio in compound. It may or may not be the same as that of molecular formula. For example, empirical formula of disulfur dioxide is [tex]{\text{SO}}[/tex].
Molecular formula:
It is chemical formula that indicates the total number and kinds of atoms in molecule. For example, molecular formula of disulfur dioxide is [tex]{{\text{S}}_2}{{\text{O}}_2}[/tex]
Step 1: Mass of sulfur (S) and fluorine (F) is to be calculated. This is done by using equation (1).
Since the given compound contains only sulfur and fluorine. So the mass of sulfur is calculated as follows:
[tex]{\text{Mass of sulfur}}\left( {\text{S}} \right) = {\text{Mass of compound}} \times {\text{percentage of Sulfur}}[/tex] ......(1)
The mass of the compound is 102.13 g/mol.
The percentage of sulfur is 62.79 %.
Substitute the values in equation (1).
[tex]\begin{aligned}{\text{Mass of sulfur}}\left( {\text{S}} \right) &= 102.13{\text{ g/mol}} \times 62.79{\text{ }}\%\\&= 102.13{\text{ g/mol}} \times \frac{{62.79}}{{100}}\\&= 64.13{\text{ g/mol}}\\\end{aligned}[/tex]
The mass offluorine (F) is calculated as follows:
[tex]{\text{Mass of fluorine}}\left( {\text{F}} \right) = {\text{Mass of compound}} - {\text{Mass of sulfur}}\left( {\text{S}} \right)[/tex] ......(2)
Substitute 102.13 g/mol for mass of the compound and 64.13 g/mol for mass of sulfur in equation (2).
[tex]\begin{aligned}{\text{Mass of fluorine}}\left({\text{F}} \right) &= {\text{102}}{\text{.13 g/mol}} - {\text{64}}{\text{.13 g/mol}}\\&= 38{\text{ g/mol}}\\\end{aligned}[/tex]
Step 2: The number of sulfur (S) and fluorine (F) in the compound is to be calculated.
The formula to calculate the number of sulfur (S)atoms in the molecule is as follows:
[tex]{\text{Number of S}} = \dfrac{{{\text{Given mass of S}}}}{{{\text{Molar mass of S}}}}[/tex] ......(3)
The given mass of S is 64.13 g/mol.
The molar mass of S is 32 g/mol.
Substitute these values in equation (3).
[tex]\begin{aligned}{\text{Number of S}} &= \frac{{{\text{64}}{\text{.13 g/mol}}}}{{{\text{32 g/mol}}}} \\&\approx 2\\\end{aligned}[/tex]
The formula to calculate the number of fluorine (F) atoms in the molecule is as follows:
[tex]{\text{Number of F}} = \dfrac{{{\text{Given mass of F}}}}{{{\text{Molar mass of F}}}}[/tex] ......(4)
The given mass of F is 38 g/mol.
The molar mass of F is 19 g/mol.
Substitute these values in equation (4).
[tex]\begin{aligned}{\text{Number of F}} &= \frac{{{\text{38 g/mol}}}}{{{\text{19 g/mol}}}}\\&= 2\\\end{aligned}[/tex]
Hence the molecular formula of the given compound is [tex]{{\mathbf{S}}_{\mathbf{2}}}{{\mathbf{F}}_{\mathbf{2}}}[/tex].
Learn more:
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2. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Stoichiometry of formulas and equations
Keywords: empirical formula, S, F, SF, S2F2, subscript, moles of F, moles of S, mass of S, mass of F and molecular formula.