Respuesta :
Hello,
Answer C:
the summation from i equals 0 to 3 of the quantity 2 times i squared plus 1
[tex]\sum_{i=0}^3[(i+1-i)*(2*i^2+1)]\\\\ =\sum_{i=0}^3[(2*i^2+1)]\\\\[/tex]
Answer C:
the summation from i equals 0 to 3 of the quantity 2 times i squared plus 1
[tex]\sum_{i=0}^3[(i+1-i)*(2*i^2+1)]\\\\ =\sum_{i=0}^3[(2*i^2+1)]\\\\[/tex]
Answer:
The correct option is C.
Step-by-step explanation:
The given equation of curve is
[tex]y=2x^2+1[/tex]
We need to find the area under the given curve from x = 0 to x = 4 using 4 rectangles and left endpoints.
We have 4 rectangles in x = 0 to x = 4. So,
[tex]\Delta x=1[/tex]
Left Riemann sum:
[tex]\sum_{i=0}^{n-1}\Delta xf(x_i)[/tex]
Using Left Riemann sum, we get
[tex]\sum_{i=0}^{4-1}(1)f(i)[/tex]
[tex]\sum_{i=0}^{3}(2i^2+1)[/tex] [tex][\because y=2x^2+1][/tex]
The area under the given curve from x = 0 to x = 4 using 4 rectangles and left endpoints is
[tex]\sum_{i=0}^{3}2i^2+1[/tex]
Therefore the correct option is C.