30-09-2017
Mathematics

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If x+y+z=9 and xy+yz+zx=26 then find x^2+y^2+z^2

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30-09-2017

Hello,

[tex](x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz\\\\
x^2+y^2+z^2=(x+y+z)^2-2*(xy+yz+xz)\\\\ =9^2+2*26=81-52\\\\ \boxed{=29} [/tex]

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