Question

In the reaction, 3Cu + 2Al3+ → 3Cu2+ + 2Al, which substance is being reduced? Cu Al3+ Cu2+ Al

Answer 1

The reaction is $3Cu+2Al^{3+}\rightarrow3Cu^{2+}+2Al$

The semi equations are hence the following : $Cu-=Cu^{2+}+2e^-, Al^{3+}+3e^-=Al$

The substance being reduced is the one that gets the electrons.

Hence here it's Al