[tex] \frac{3}{9} [/tex] + [tex] \frac{3}{27} [/tex] equals [tex] \frac{4}{9} [/tex].
First, simplify [tex] \frac{3}{9} [/tex] to [tex] \frac{1}{3} [/tex] and also [tex] \frac{3}{27} [/tex] to [tex] \frac{1}{9} [/tex]. Your problem should look like: [tex] \frac{1}{3} [/tex] + [tex] \frac{1}{9} [/tex].
Second, find the least common denominator of [tex] \frac{1}{3} [/tex] and [tex] \frac{1}{9} [/tex] to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: [tex] \frac{1x3}{3x3} [/tex] + [tex] \frac{1}{9} [/tex].
Fourth, simplify to get the denominators the same. Your problem should look like: [tex] \frac{3}{9} [/tex] + [tex] \frac{1}{9} [/tex].
Fifth, join the denominators. Your problem should look like: [tex] \frac{3+1}{9} [/tex].
Sixth, simplify. Your problem should look like: [tex] \frac{4}{9} [/tex], which is the answer.
