Question

What substitution should be used to rewrite 4x12 – 5x6 – 14 = 0 as a quadratic equation? u = x2 u = x3      u = x6      u = x12

Answer 1

Sent a picture of the solution to the problem (s).

Answer 2

Answer: $u=x^6$

Explanation:

A quadratic equation is an equation written in the form

$au^2 + bu + c=0$ (1)

where a,b,c are coefficients and where u is the variable.

Our original equation is:

$4x^{12} - 5x^6 -14=0$

If we make the substitution $u=x^6$, we obtain

$4u^2 -5u-14 =0$

Which corresponds to eq.(1), with coefficients a=4, b=-5, c=-14.