yashey28 yashey28
  • 29-09-2017
  • Mathematics
contestada

write an equation of the circle that is tangent to both axes with radius sqrt5 and center in quadrant 3

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jdoe0001 jdoe0001
  • 29-09-2017
check the picture below.

[tex]\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 ~~ \begin{array}{lllll} center~(&\quad {{ h}},&\quad {{ k}}\quad )\qquad radius=&{{ r}}\\ &-\sqrt{5}&-\sqrt{5}&\sqrt{5} \end{array} \\\\\\\ [x-(-\sqrt{5})]^2+[y-(-\sqrt{5})]^2=(\sqrt{5})^2 \\\\\\ (x+\sqrt{5})^2+(y+\sqrt{5})^2=5[/tex]
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WHOEVER KNOWS HOW TO DO THIS ( in the picture above ) AND COULD GIVE ME ALL THE ANSWERS, ILL VENMO YOU $55 DOLLARS !! FOR ALGEBRA ( 10 QUESTIONS ) JUST DM ME