Question

Ionization energy is the energy needed to eject an electron from an atom. Compute the ionization energy of a hydrogen atom in its fifth excited state (n = 6).

Answer 1

Hydrogen has only 2 electrons, so it can't lose 5 electrons!!!

Answer 2

The ionization energy of a hydrogen atom in its fifth excited state (n = 6). is

E=36.46kJ/mol

What is Ionization energy?

Generally, Ionization energy is simply defined as the energy needed to eject an electron from an atom.

In conclusion,  Rydberg Expression

1/\lambda= R[1/n^2_1-1/n^2_2]

Therefore

$1/\lambda= R[1/n^2_1-0]\\\\1/\lambda= R[1/n^2_1]\\\\1/\lambda= R[1/36]\\\\\lambda= 36/1.097*10^7\\\\\lambda= 32.816 *10^{−7}$

In conclusion

$E=hc/\lambda\\\\E=6.626*10^{-34}*3*10^{8}/32.816*10^{-7}\\\\E=6.0575*10^{-20}J$

In J/mol

$E=6.0575*10^{-20}*6.02*10^{23}$

E=36.46kJ/mol

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