Question

What is the concentration of k+ ions in a 0.025 m k2co3 solution assuming complete dissociation?

Answer 1

The answer to this question would be: 0.050 m

In this question, you have a 0.025m concentration of K2CO3 or potassium carbonate solution. The compound will dissociate into 2 K+ and 1 (CO3)2-

Then the amount of K+ ion in this solution assuming complete dissociation should be: 2/1 * 0.025m= 0.050m

Answer 2

The complete dissolution of 0.025 M $\rm K_2CO_3$ will result in 0.050 M $\rm K^+$.

The complete dissolution of $\rm K_2CO_3$ will result in:

$\rm K_2CO_3\;\rightarrow\;2\;K^+\;+\;CO_3^2^-$

1 molecule of $\rm K_2CO_3$ will gives 2 molecules of $\rm K^+$.

So 0.025 M $\rm K_2CO_3$ will give: 1 M

0.025 M $\rm K_2CO_3$ = $\rm 0.025\;\times\;2\;K^+$ M

= 0.05 M $\rm K^+$.

Thus the complete dissolution of 0.025 M $\rm K_2CO_3$ will result in 0.050 M $\rm K^+$

For more information, refer to the link:

https://brainly.com/question/788696