Question

The volume of a gas sample is 405 mL at 10.0 atm and 467 K. What volume, in mL, will it occupy at 4.29 atm and the same temperature?

Answer 1

Use the formula pv=nrt
P=pressure in pa
V=volume in m3
R=molar gas constant
N=no of moles in moles
T=temperature in k

Answer 2

The final volume of the gas at the given pressure and temperature is 944.1 mL.

The given parameters;

• initial volume of the gas, V₁ = 405 mL
• initial pressure of the gas, P₁ = 10 atm
• final pressure of the gas, P₂ = 4.29 atm

The final volume of the gas at the given pressure and temperature is calculated by applying Boyle's law;

$P_1V_1 = P_2v_2\\\\V_2 = \frac{P_1V_1}{P_2} \\\\V_2 = \frac{10 \times 405 }{4.29} \\\\V_2 = 944.1 \ mL$

Thus, the final volume of the gas at the given pressure and temperature is 944.1 mL.

Learn more about Boyle's law here: https://brainly.com/question/469270