Respuesta :
x = larger number
y = smaller number
x = 4y - 9
x + y = 76
4y - 9 + y = 76
5y = 76 + 9
5y = 85
y = 85/5
y = 17
x + y = 76
x + 17 = 76
x = 76 - 17
x = 59
ur numbers are 17 and 59
y = smaller number
x = 4y - 9
x + y = 76
4y - 9 + y = 76
5y = 76 + 9
5y = 85
y = 85/5
y = 17
x + y = 76
x + 17 = 76
x = 76 - 17
x = 59
ur numbers are 17 and 59
Answer:
17 and 59
Step-by-step explanation:
Let's find the answer by assuming the following:
L=larger number
S=smaller number
The first condition is: 'L' is nine less than four times 'S' but, because:
(four times 'S') is the same as 4*S then:
('L' is nine less than four times 'S') is equal to ('L' is nine less than 4*S), which means:
L+9=4*S (eq. 1)
Second condition is: the sum of the two numbers is 76, so:
L+S=76 which can be written as:
S=76-L using this relation in eq. 1 we have:
L+9=4*S
L+9=4*(76-L)
L+9=304-4L
L+4L=304-9
5L=295
L=295/5
L=59
And also we have:
L+S=76
S=76-L
S=76-59
S=17
In conclusion, the two numbers are 17 and 59.