Question

Consider 01 .85 g mixture of sodium chloride and sodium nitrate powders. After adding 100 mL of water and an excess of .5 M silver nitrate solution, the white solid produced is collected and dried. The solid’s weight is .643g. Find the percent of sodium chloride in the original mixture.

Answer 1

fprime(2) =-5*f(2)*(5+f(2)) = -5*6*(5+6) = -330 gms / minute -330gms / minute = -330 gms / 60 sec = 5.5 gms / sec Therefore the weight of the ice at time = 2 is decreasing by 5.5 gms / sec

Its weight after 1 second will be 6 - 5.5 = 0.5 gms