Respuesta :
Answer: The precipitate is [tex]Ba_3(PO_4)_2[/tex] and 1 molecule of Barium phosphate and 6 molecules of Potassium nitrate is formed.
Explanation: We are given Barium nitrate and Potassium phosphate , that will lead to the formation of Barium phosphate and Potassium nitrate.
As we know that these solutions are present in water, therefore we will obtain Barium phosphate as a precipitate because Barium phosphate is insoluble in water and Potassium nitrate is soluble in water. Thus the reaction is
[tex]Ba(NO_3)_2(aq.)+K_3PO_4(aq.)\rightarrow Ba_3(PO_4)_2(ppt.)+KNO_3(aq.)[/tex]
To know how many molecules are formed at the end, we need to balance the above equation.
Balancing the equation, we get:
[tex]3Ba(NO_3)_2(aq.)+2K_3PO_4(aq.)\rightarrow Ba_3(PO_4)_2(ppt.)+6KNO_3(aq.)[/tex]
Thus, we get 1 molecule of Barium phosphate as a precipitate and 6 molecules of Potassium nitrate which is easily soluble in water.
Answer:
The barium phosphate is precipitate and 1 molecule is formed.
According to the reaction mentioned,
[tex]\rm \bold { 3BaNO_3_(_a_q_)+ 2K_3PO_4_(_a_q_) \rightarrow Ba_3(PO_4)_2_(_p_p_t_)+ 6 KNO_3_(_a_q_)}[/tex]
We can conclude that, the barium phosphate is precipitate and 1 molecule is formed.
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https://brainly.com/question/16225195?referrer=searchResults
