well, again y=5x+4 is in slope-intercept form, therefore [tex]\bf y=\stackrel{slope}{5}x+4[/tex].
so then, a parallel line to a line with that equation, will also have the same slope, therefore, what's the equation of a line whose slope is 5 and goes through 8, -2?
[tex]\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{8}}\quad ,&{{ -2}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 5
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=5(x-8)\implies y+2=5x-40
\\\\\\
y=5x-40-2\implies y=5x-42[/tex]
