Question

Determine the discriminant for the quadratic equation 0 = –2x2 + 3. Based on the discriminant value, how many real number solutions does the equation have?

Discriminant = b2 – 4ac


real number solutions

Answer 1

Determine the discriminant for the quadratic equation 0 = –2x2 + 3. Based on the discriminant value, how many real number solutions does the equation have?  Remember that the discriminant is calculated using the coefficents a, b and c.  Given 0 = -2x^2 + 0x + 3, the coeff. are a=-2, b=0 and c=3.

The discriminant is b^2 - 4ac.  Here, the discriminant is 0^2 - 4(-2)(3) = 24.

Since the discriminant is positive, you have two real, unequal roots.

Answer 2

The positive value of the discriminant implies that there are two real unequal roots and this can be determined by using the formula of the discriminant.

Given :

The quadratic equation is $(0=-2x^2+3)$.

The following steps can be used in order to determine the total number of real solutions does the equation have:

Step 1 - Write the given quadratic equation.

$0=-2x^2+0x+3$

Step 2 - The formula of discriminant is given below:

$D = b^2-4ac$

where 'b' is the coefficient of 'x', 'a' is the coefficient of $x^2$, and 'c' is the constant.

Step 3 - Now, substitute the values of a, b, and c in the above formula.

$D = (0)^2-4\times (-2)\times 3$

$D = 24$

Step 4 - The positive value of the discriminant implies that there are two real unequal roots.

For more information, refer to the link given below:

https://brainly.com/question/12657401