Jetski
Jetski Jetski
  • 28-09-2017
  • Mathematics
contestada

how would you solve #2 and #3?

how would you solve 2 and 3 class=

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choixongdong
choixongdong choixongdong
  • 28-09-2017
total of all given sides:
3x^4 - 4 + 4x^3 + 6x + 4x^4 -2x^2 - 3x + 5x^3 - 2x^2
= 7x^4 +  9x^3 - 4x^2 + 3x - 4

missing side = perimeter -  total given sides
missing side = (7x^4 + 9x^3 - 6x^2 + 10) - (7x^4 + 9x^3 - 4x^2 + 3x - 4)
missing side = 7x^4 + 9x^3 - 6x^2 + 10 - 7x^4  -9x^3 + 4x^2 - 3x + 4
missing side =  - 2x^2  - 3x + 14

answer
 - 2x^2  - 3x + 14


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