Question

The resistivity of a silver wire with a radius of 5.04 × 10–4 m is 1.59 × 10–8 ω · m. if the length of the wire is 3.00 m, what is the resistance of the wire?

Answer 1

5.98 x 10^-2 ohms. Resistance is defined as: R = rl/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire. So plugging into the formula, the known values, including the area of a circle being pi*r^2, gives: R = 1.59x10^-8 * 3.00 / (pi * (5.04 x 10^-4)^2) R = (4.77 x 10^-8) / (pi * 2.54016 x 10 ^-7) R = (4.77 x 10^-8) / (7.98015 x 10^-7) R = 5.98 x 10^-2 ohms So that wire has a resistance of 5.98 x 10^-2 ohms.

Answer 2

The resistivity of a silver wire is 5.98 x 10^-2 ohms.

How do find the resistivity of a silver wire?

Resistance is defined as: R = r*l/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire.

Substituting into the formula, the known values, including the area of a circle being pi*r^2, gives:

R = 1.59x$10^{-8}$ * 3.00 / ($\pi$ * (5.04 x $10^{-4}$)²)

R = (4.77 x$10^{-8}$) / (pi * 2.54016 x $10^{-7}$)

R = (4.77 x $10^{-8}$) / (7.98015 x $10^{-7}$)

R = 5.98 x $10^{-2}$ ohms

The wire has a resistance of 5.98 x 10^-2 ohms.

Learn more about Resistance here: https://brainly.com/question/14883923

#SPJ2