The pressure in a car tire is 298 kilopascals at 300 Kelvin. After a long drive, the pressure becomes 325 kilopascals. Which law will you use to calculate the new temperature in the tire assuming that the volume is constant?

Respuesta :

the answer to your question is



Gay-Lussac’s law

Answer: Gay Lussac's law

The final temperature of the gas will be 275 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

[tex]P\propto T[/tex]     (At constant volume and number of moles)

[tex]{P_1\times T_1}={P_2\times T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas  = 298 kPa

[tex]P_2[/tex] = final pressure of gas = 325 kPa

[tex]T_1[/tex] = initial temperature of gas  = 300 K

[tex]T_2[/tex] = final temperature of gas = ?

[tex]{298\times 300}={325\times T_2}[/tex]

[tex]T_2=275K[/tex]

Therefore, the final temperature of the gas will be 275 K.

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