now, "21 more photos" is 21 added to the already printed 28, so 21 more is 28+21 photos, or 49,
[tex]\bf \begin{array}{ccll}
photos&minutes\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
28&8\\
49&m
\end{array}\implies \cfrac{28}{49}=\cfrac{8}{m}\implies m=\cfrac{49\cdot 8}{28}[/tex]
what about 35 more? well, it already printed 49, and 35 more would then be 84,
[tex]\bf \begin{array}{ccll}
photos&minutes\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
28&8\\
84&m
\end{array}\implies \cfrac{28}{84}=\cfrac{8}{m}\implies m=\cfrac{84\cdot 8}{28}[/tex]