Our three consecutive integers can be represented as
X → first integer
X + 1 → second integer
X + 2 → third integer
If the sum of our three consecutive integers is 63, our equation will read...
X + X + 1 + X + 2 = 63
Now, we can simplify on the left. Once we simplify, our equation will now read
3x + 3 = 63
-3 -3 ← subtract 3 on both sides
3x = 60 ← divide both sides by 3
X = 20
Our three consecutive integers can be represented as
X → first integer = 20
X + 1 → second integer = 21
X + 2 → third integer = 22
Therefore, the three consecutive integers are 20, 21, and 22.
