Respuesta :

There is a solution. Starting from C−1(A+X)B−1=In C−1(A+X)B−1=In, multiply both of the sides of the equation, by C and multiply both sides of the equation by B.


In other terms, this is the solution:


Given: C^(-1)(A + X)B^(-1) = In


= CC^(-1)(A + X)B^(-1)B = CInB



= In(A + X)In = CB



= AInIn + XInIn = CB


= A + X = CB


X = CB – A

 

The final answer Is X = CB – A

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