Question

How many grams of ko2 are needed to form 8.5 g of o2?

Answer 1

Assuming molar mass of O2 = 32 gm/mole required moles of O2 = 8.5/32 = 0.266 moles requied moles of KO2= (4/3)*0.266 = 0.354 moles Molecular weight of KO2 = 39+32 = 71 gm/mole Weight = 71*0.354 = 25.134 gms