Find the values of x on the curve y = cos x 2 + sin x at which the tangent is horizontal. (let n be an integer. enter your answers as a comma-separated list.)
y = cos^2(x) + sin(x) y' = --2sin(x) + cos(x) = 0 first derivative. Set to 0 for horizontal tangent. -2sin(x) = -cos(x) Tan(x) = 1/2 x = 26.565 degrees
