Question

The equation of line q is 5y - 4x = 10. Write the standard form of the equation of the line that fits the following description: parallel to q and passes through the point at (-15, 8)

Answer 1

The line parallel to 5y - 4x=10, that passes through (-15, 8) is
y=4/5x +20

Answer 2

Answer:

y =  $(\frac{4}{5})$x + 20

Step-by-step explanation:

The equation of line q is 5y - 4x = 10

                                       5y = 4x + 10

                                       y = $\frac{4}{5}x+2$

If a line is parallel to this line the slope of the line will be the same as the given line = $(\frac{4}{5})$

Let the parallel line is y = mx + c

where m = slope

and    c = y-intercept

equation will be y = $\frac{4}{5}x+c$

This line passes through (-15, 8)

so   8 = (-15)  $(\frac{4}{5})$ + c

8 = -12 + c

c = 12 + 8

c = 20

Now the equation of the parallel line will be y =  $(\frac{4}{5})$x + 20