Respuesta :

[tex]\bf \textit{height of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2}\qquad \begin{cases} s=\textit{length of a side}\\ ---------\\ s=16\sqrt{3} \end{cases}\implies h=\cfrac{16\sqrt{3}\cdot \sqrt{3}}{2} \\\\\\ h=\cfrac{16\cdot 3}{2}\implies h=8\cdot 3\implies h=24[/tex]

Answer:24

Step-by-step explanation:

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