Question

Please help me with my math homework! 20 points!

A culture of 1.08×10^15 bacteria is in petri dish A. A culture of 2.7×10^11 bacteria is in petri dish B.

How many times greater is the number of bacteria in petri dish A than petri dish B?

Enter your answer, in standard notation, in the box.

Answer 1

To find the number of times the bacteria in petri dish A than petri dish B, let us divide.

So, number of times = $\frac{Number of times bacteria in petri dish A}{Number of times bacteria in petri dish B}$

$= \frac{1.08(10^{15} )}{2.7(10^{11} )}$

= 0.4 × $10^{4}$

= 4000

Hence, the number of bacteria in petri dish A is 4000 times the number of bacteria in petri dish B.