A system of linear equations can be solved by elimination, substitution or using graphs.
The values of x and y for [tex]6x + 7y= 59[/tex] and [tex]4x + 5y =41[/tex] are 4 and 5, respectively.
Given
[tex]6x + 7y= 59[/tex]
[tex]4x + 5y =41[/tex]
Make x the subject in [tex]4x + 5y =41[/tex]
[tex]4x = 41 - 5y[/tex]
Divide by 4
[tex]x = \frac 14(41 - 5y)[/tex]
Substitute [tex]x = \frac 14(41 - 5y)[/tex] in [tex]6x + 7y= 59[/tex]
[tex]6 \times \frac 14(41 - 5y)+ 7y = 59[/tex]
[tex]\frac 32(41 - 5y)+ 7y = 59[/tex]
Multiply through by 2
[tex]2 \times \frac 32(41 - 5y)+ 2 \times 7y = 2 \times 59[/tex]
[tex]3(41 - 5y)+ 14y = 118[/tex]
Open brackets
[tex]123 - 15y+ 14y = 118[/tex]
Collect like terms
[tex]- 15y+ 14y = 118 - 123[/tex]
[tex]-y = -5[/tex]
[tex]y = 5[/tex]
Substitute [tex]y = 5[/tex] in [tex]x = \frac 14(41 - 5y)[/tex]
[tex]x = \frac 14(41 - 5 \times 5)[/tex]
[tex]x = \frac 14(41 - 25)[/tex]
[tex]x = \frac 14(16)[/tex]
[tex]x = 4[/tex]
Hence, the solution to the system of linear equations is:
[tex]x = 4[/tex]
[tex]y = 5[/tex]
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