Triangle MRN is created when an equilateral triangle is folded in half. What is the value of y?

A. 2√3 units
B. 4 units
C. 4√3 units
D. 8 units

Triangle MRN is created when an equilateral triangle is folded in half What is the value of y A 23 units B 4 units C 43 units D 8 units class=

Respuesta :

we know that

If Triangle MRN is created when an equilateral triangle is folded in half

then

[tex]RM=\frac{1}{2}*MN[/tex]

[tex]MN=6+2=8\ units[/tex]

so

[tex]RM=\frac{1}{2}*8=4\ units[/tex]

Applying the Pythagorean Theorem in triangle MRN

[tex]MN^{2}=NR^{2}+RM^{2}[/tex]

we have

[tex]MN=8\ units[/tex]

[tex]RM=x=4\ units[/tex]

[tex]NR=y[/tex]

substitute

[tex]8^{2}=y^{2}+4^{2}[/tex]

solve for y

[tex]y^{2}=8^{2}-4^{2}[/tex]

[tex]y^{2}=48[/tex]

[tex]y=\sqrt{48}=4\sqrt{3}\ units[/tex]

therefore

the answer is the option C

[tex]4\sqrt{3}\ units[/tex]

Answer:

The correct option is C.

Step-by-step explanation:

It is given that triangle MRN is created when an equilateral triangle is folded in half.

It means original equilateral is triangle MNO and NR is a perpendicular bisector. The side length of the triangle is

[tex]MO=NO=MN=MS+SN=2+6=8[/tex]

Since NR is a perpendicular bisector, therefore

[tex]RM=\frac{MO}{2}=\frac{8}{2}=4[/tex]

Using Pythagoras property in triangle MNR,

[tex]MR^2+NR^2=MN^2[/tex]

[tex]4^2+y^2=8^2[/tex]

[tex]y^2=64-16[/tex]

[tex]y=\sqrt{48}[/tex]

[tex]y=4\sqrt{3}[/tex]

Therefore option C is correct.

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