Respuesta :
2(|x−3|)−4≥10
Step 1: Add 4 to both sides.2(|x−3|)−4+4≥10+42(|x−3|)≥14Step 2: Divide both sides by 2.2(|x−3|)2≥142|x−3|≥7Step 3: Solve Absolute Value.|x−3|≥7We know eitherx−3≥7orx−3≤−7x−3≥7(Possibility 1)x−3+3≥7+3(Add 3 to both sides)x≥10x−3≤−7(Possibility 2)x−3+3≤−7+3(Add 3 to both sides)x≤−4
the answer is
x≥10or x≤−4
Step 1: Add 4 to both sides.2(|x−3|)−4+4≥10+42(|x−3|)≥14Step 2: Divide both sides by 2.2(|x−3|)2≥142|x−3|≥7Step 3: Solve Absolute Value.|x−3|≥7We know eitherx−3≥7orx−3≤−7x−3≥7(Possibility 1)x−3+3≥7+3(Add 3 to both sides)x≥10x−3≤−7(Possibility 2)x−3+3≤−7+3(Add 3 to both sides)x≤−4
the answer is
x≥10or x≤−4
Hi TeddyBR
Add 4 to both sides
add 10 + 4 to 14
divide both sides by 2
divide 14/2 to 7
break down the problems into these two equations
x - 3 ≥ 7
-(x - 3) ≥ 7
Lets first solve the first equation which is x - 3 ≥ 7 and that would be x ≥ 10 and lets solve the other one which is -(x - 3) ≥ 7 and that would be x ≤ -4
Gather both solutions
Answers: x ≥ 10 and x ≤ -4.
Add 4 to both sides
add 10 + 4 to 14
divide both sides by 2
divide 14/2 to 7
break down the problems into these two equations
x - 3 ≥ 7
-(x - 3) ≥ 7
Lets first solve the first equation which is x - 3 ≥ 7 and that would be x ≥ 10 and lets solve the other one which is -(x - 3) ≥ 7 and that would be x ≤ -4
Gather both solutions
Answers: x ≥ 10 and x ≤ -4.