Respuesta :

2(|x−3|)−4≥10
Step 1: Add 4 to both sides.2(|x−3|)−4+410+42(|x−3|)≥14Step 2: Divide both sides by 2.2(|x−3|)2142|x−3|≥7Step 3: Solve Absolute Value.|x−3|≥7We know eitherx−3≥7orx−3−7x−3≥7(Possibility 1)x−3+37+3(Add 3 to both sides)x≥10x−3−7(Possibility 2)x−3+3−7+3(Add 3 to both sides)x≤4
the answer is 
x≥10or x≤−4



Hi TeddyBR

Add 4 to both sides

add 10 + 4 to 14

divide both sides by 2

divide 14/2 to 7

break down the problems into these two equations

x - 3 ≥ 7

-(x - 3) ≥ 7

Lets first solve the first equation which is x - 3 ≥ 7 and that would be x ≥ 10 and lets solve the other one which is -(x - 3) ≥ 7 and that would be x  -4

Gather both solutions

Answers: x ≥ 10 and x ≤ -4.
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