Question

Silver nitrate, agno3, reacts with iron(iii) chloride, fecl3, to give silver chloride, agcl, and iron(iii) nitrate, fe(no3)3. a solution containing 18.00 g of agno3 was mixed with a solution containing 32.40 g of fecl3. how many excess grams of the excess reactant remain after the reaction is over?

Answer 1

3 AgNO3 + FeCl3 = Fe(NO3)3 + 3 AgCl moles AgNO3 = 18.0 g/ 169.87 g/mol=0.106 moles FeCl3 required = 0.106/3=0.0353 mass FeCl3 = 162.206 g/mol x 0.353 mol=5.73 g mass FeCl3 in excess = 32.4 - 5.73 =26.7 g. 26.7 gram of excess reactant remain after the reaction is over