First, we write the balanced equation for the reaction:
Na₂Cr₂O₇ + (CH₃COO)₂Hg → 2CH₃COONa + HgCr₂O₇(s)
Next, we determine the number of moles of each substance. For this, we require the molar masses. These are:
Na₂Cr₂O₇ - 262 g/mol
(CH₃COO)₂Hg - 319 g/mol
CH₃COONa - 82 g/mol
HgCr₂O₇ - 416 g/mol
Now, the moles are:
Na₂Cr₂O₇ - 5.102 / 262 = 0.02
(CH₃COO)₂Hg - 16.38 / 319 = 0.05
From the equation, we can see that mercury (II) acetate is in excess, so the product moles will be calculated from sodium dichromate. These will be:
0.02
The mass will be:
0.02 * 416
8.32 grams of solid product
