Respuesta :

[tex]k^2-11\ \ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\k^2-(\sqrt{11})^2=(k-\sqrt{11})(k+\sqrt{11})\\\\if\ k^2-11=0\ then\ k-\sqrt{11}=0\ or\ k+\sqrt{11}=0\\\downarrow\\k=\sqrt{11}\ or\ k=-\sqrt{11}[/tex]
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