The distribution of the time it takes for different people to solve a certain crossword puzzle is strongly skewed to the right, with a mean of 30 minutes and a standard deviation of 15 minutes. the distribution of z-scores for those times is

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Answer: Skewed to right with mean 0 and S.D. 1 Explanation: Let's assume the z-scores as a linear transformation. then z=(x-mean)/S.D. = (x-30)/15 z(mean) = (30-30)/15= 0 z(sigma) = 15/15 = 1 Note: Shape does not change.

z-scores illustrates how far a data element is, from the mean of the dataset.

  • The distribution of z-scores of the mean is 0
  • The distribution of z-scores of the standard deviation is -1

Given

[tex]\mu = 30[/tex] --- the mean

[tex]\sigma = 15[/tex] --- the standard deviation

z-score is calculated using:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

(a) The z-score of the mean

This means that:

[tex]x = \mu[/tex]

[tex]x = 30[/tex]

So, we have:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

[tex]z = \frac{30 - 30}{15}[/tex]

[tex]z = \frac{0}{15}[/tex]

[tex]z = 0[/tex]

(b) The z-score of the standard deviation

This means that:

[tex]x = \sigma[/tex]

[tex]x = 15[/tex]

So, we have:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

[tex]z = \frac{15 - 30}{15}[/tex]

[tex]z = \frac{-15}{15}[/tex]

[tex]z = -1[/tex]

Hence, the distributions of z-score for the mean and the standard deviation are 0 and -1 respectively.

Read more about z-scores at:

https://brainly.com/question/13299273

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