Respuesta :
[tex]3x^2- 24x + 36=\\
3(x^2-8x+12)=\\
3(x^2-6x-2x+12)=\\
3(x(x-6)-2(x-6))=\\
3(x-2)(x-6)[/tex]
[tex]3x^{2}-24x+36=3(x^{2}-8x+12)=3(x^{2}-2x-6x+12)= \\ \\ =3[x(x-2)-6(x-2)]=3(x-6)(x-2)[/tex]
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