Question

4y=3/x^2+2, what is the value of x?

Answer 1

$4y=\frac{3}{x^2}+2$   (1/equation)
$\frac{1}{4y}=\frac{1}{\frac{3}{x^2}}+\frac{1}{2}$ 
$\frac{1}{4y}=\frac{x^2}{3}+\frac{1}{2}$ (*3)
$\frac{3}{4y}=\frac{3x^2}{3}+\frac{3}{2}$
$\frac{3}{4y}=x^2+\frac{3}{2}$ 
$\frac{3}{4y}-\frac{3}{2}=x^2$
$x^2=\frac{3}{4y}-\frac{3}{2}$
$\sqrt{x^2}=\sqrt{\frac{3}{4y}-\frac{3}{2}}$
$|x|= \sqrt{\frac{3}{4y}-\frac{3}{2}}$
$x=\pm\sqrt{\frac{3}{4y}-\frac{3}{2}$