Question

find the slope of the line having equation 4x- 3y= 13

Answer 1

First we must transform the equation above into an equation of the form:

y=mx+C

The value of m is actually the slope.

$4x-3y=13\\ \\ 3y=4x-13\\ \\ \frac { 1 }{ 3 } \cdot 3y=\frac { 1 }{ 3 } \left( 4x-13 \right) \\ \\ y=\frac { 4 }{ 3 } x-\frac { 13 }{ 3 }$

As m=4/3, this is in fact your slope.

Answer:

4/3

Answer 2

Let's solve for x.

4x−3y=13

Add 3y to both sides.

4x−3y+3y=13+3y

4x=3y+13

Divide both sides by 4.

4x/4=3y+13/4

x = 3/4y+13/4




Let's solve for y.

4x−3y=13

Add -4x to both sides.

4x−3y+−4x=13+−4x

−3y=−4x+13

Divide both sides by -3.

−3y/−3=−4x+13/−3

y=4/3x+−13/3