Respuesta :

Answer:

Another length of this diagram FE=12.

Step-by-step explanation:

According to diagram

In triangle FED, EM is perpendicular bisector of FD.

In ΔFED, EM ⊥ FD and FM=MD

In ΔFME and ΔDME

FM=DM                       (Given)

∠FME=∠DME             (each 90°)

ME=ME                       (Common)

ΔFME ≅ ΔDME  (By SAS congruence property)

Therefore, FE≅DE  (by CPCT)

But DE=12

So, FE=12

Thus, Another length of this diagram FE=12.

Ver imagen isyllus

Answer: You can determine FE=DE=12 as other length from the given diagram

Step-by-step explanation:

Let O be the intersecting point of the line segment GE and DF in the given figure.

Now, in triangle FED, we can say EO is perpendicular bisector of FD.

Since EO ⊥ FD and FO=OD

Therefore, in ΔFOE and ΔDOE

OE=OE                       [Common]

∠FOE=∠DOE              [each right angle]

FO=DO                        [Given]

⇒ ΔFOE ≅ ΔDOE  [By SAS congruence postulate]

FE≅DE   (by CPCT)

Since DE=12   [Given]

 FE=12

Thus, the other length we can determine for the given diagram is FE=12.

Ver imagen JeanaShupp
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