Question

-6+8(6x+2) < 7x+10

What is the answer to this inequality?
The answer choices are
A. x < 0
B. No solution
C. All numbers
D. x > 0

Answer 1

x < 0

First, distribute the 8 to (6x+2)
48x + 16

-6 + 16 +48x < 7x + 10

Combine like-terms
48x - 7x < 10 + 6 - 16

Simplify
41x < 0

Therefore, x < 0

Answer 2

$-6+8(6x+2) \ \textless \ 7x+10$ 

$8(6x+2)-6\ \textless \ 7x+10$ 

$48x+16-6\ \textless \ 7x+10$ 

$48x+10\ \textless \ 7x+10$ 

$48x\ \textless \ 7x$ 

$48x-7x\ \textless \ 0$ 

$41x\ \textless \ 0$

$x\ \textless \ 0$