Question

A proton and an electron are separated by 6.5 Ã 10â10 m. (a) calculate the magnitude of the electric force that the proton exerts on the electron

Answer 1

Couloumb's law : (1/(4*pi*epsilon_nought))*((q_1*q_2)/r^2)

8.99*10^9* ((charge of a proton*charge of an electron)/(6.5*10^10m)^2)

8.99*10^9* ((1.602*10^-19)(|-1.602*10^-19|)/((6.5*10^10)^2)

=5.4608*10^-50

Answer 2

We have that the magnitude of the electric force that the proton exerts on the electron

$F=5.45*10^{-10}N$

From the question we are told that

proton and an electron are separated by 6.5 Ã 10â10 m

Generally the equation for the Force  is mathematically given as

$F=\frac{kq_1q_2}{r^2}\\\\F=\frac{9*10^{9}*(1.6*10^{-19})^2}{(6.5*10^{-10})^2}$

$F=5.45*10^{-10}N$

Therefore

the magnitude of the electric force that the proton exerts on the electron

$F=5.45*10^{-10}N$

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