Question

The Diameter of a chlorine atom is 200. Pm. How many chlorine atoms are required to line up end to end to stretch a distance of 1.0mm? Use 'E' for scientific notation.

Answer 1

Diameter = 200pm
200pm -> mm
200pm *^-12 / 1*10^-3 = .0000002
2.0*10-7x mm = 1.0mm
Divide x on both sides

Answer 2

Answer:

5e6 atoms

Explanation:

Hello,

At first, we must convert from pm to mm to find the diameter of the chlorine atom in mm:

$200pm*\frac{1e-12m}{1pm} *\frac{1mm}{1e-3m} =2e-7mm$

Now, by dividing the total distance by the distance of one chlorine atom, we can compute how many chlorine atoms are required as they are aligned:

$Cl,atoms=\frac{1.0mm}{2e-7mm}=5e6atoms$

Best regards.