Question

An iron cube measures 3.12cm* 567cm*22.0 dm. What is the mass of this cube knowing Fe a density of 721g/mL?

Answer 1

Calculate formula and then substitute values into the formula for mass.

V = lwh
    = (3.12)(527)(220)
    = 361732.8
M = Dv
    = (721)(361731.8)
    ≈ 2608086.28 kg

I'm not exactly sure so :/