Question

How do you solve this quadratic equation, 3x2+4x-5=0

Answer 1

$3x^2+4x-5=0 \\ Solve\ using\ formular \ \ \ \boxed {x={ \frac{-b\pm \sqrt{b^2-4ac} }{2a} }} \\ \\ x={ \frac{-4 \pm \sqrt{4^2-4(3)(-5)} }{2(3)} }}$