Question

Calculate the number of moles of Cl atoms in 3.61×1024 formula units of magnesium chloride, MgCl2

Answer 1

For ever molecule of MgCl2, there are 2 Cl atoms.

3.61 x 10^24 molecules MgCl2 x 2 = 7.22 x 10^24 atoms Cl

7.22 x 10^24 atoms Cl x 1 mol / 6.022 x 10^23 = 12.0 moles Cl

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Answer 2

The number of moles of Cl atoms in the given formula units of the magnesium chloride is 12

To determine the number of moles of Cl atoms in 3.61×10²⁴ formula units of magnesium chloride,

First, we will determine the number of Cl atoms in the 3.61×10²⁴ formula units of magnesium chloride

From the chemical formula for magnesium chloride MgCl₂,

Each formula units of magnesium chloride contains 2 Cl atoms

∴  3.61×10²⁴ formula units of magnesium chloride will contain  2 × 3.61×10²⁴ atoms of Cl

2 × 3.61×10²⁴  = 7.22×10²⁴ atoms of Cl

Therefore, there are 7.22×10²⁴ atoms of Cl in the 3.61×10²⁴ formula units of magnesium chloride

Now, for the number of moles of Cl atoms

From the formula

$Number \ of \ moles = \frac{Number \ of \ atoms}{Avogadro's \ number}$

∴ $Number \ of \ moles \ of \ Cl \ atoms= \frac{7.22 \times 10^{24} }{6.022 \times 10^{23} }$

$Number \ of \ moles \ of \ Cl \ atoms= 11.989$

Number of moles of Cl atoms ≅ 12

Hence, the number of moles of Cl atoms in the given formula units of the magnesium chloride is 12

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