Question

The perimeter of a rectangle is 700700 yards. what are the dimensions of the rectangle if the length is 3030 yards more than the​ width

Answer 1

b:lenght
a:width
b= a+3030
P=2×(a+b)
700700=2×(a+a+3030)
700700÷2=2a+3030
a=173660
b=176690