Let us say that Cp is the specific heat of the metal object. Then we do a heat balance (heat lost by metal = heat gained by water):
- 19g * Cp * (22degC – 96degC) = 75g * 4.184J/g degC * (22degC – 18degC)
Cp = 0.893 J/g degC
Answer;
Specific heat of the metal object = 0.893 J/g°C
Explanation and solution;
Quantity of heat = mass × specific heat capacity × change in temperature
ΔQ = Mcθ
Heat lost by the metal object = Heat gained by water
Heat lost by the metal object
= Mass of the metal object × specific heat of the metal ×change in temp
= 19 x specific heat ×( 22 - 96)
= 1406 × specific heat
Heat gained by water
= Mass of water × specific heat capacity of water × change in temperature
= 75 x 4.186 x ( 22 - 18)
= 1255.8 J
Therefore;
= 1406 x specific heat = 1255.8
Specific heat = 0.893 J/g°C
