Question

I need one more last help please. Thanks!

Answer 1

Hi Gary :)
I hope you are well today.

One rule of logarithms is $log_{b} ( \frac{m}{n} ) = log_b(m)-log_b(n)$

The square root can be written as n to the 1/2 power, then $\sqrt{n} = n^{ \frac{1}{2} }$

So rewrite $log_b[( \frac{57}{74})^ \frac{1}{2} ]$

Following the rule we finally rewrite the logarithm as:

$\frac{1}{2} log_b(57)- \frac{1}{2} log_b(74)$

Thus, our answer is B