Question

the length of a rectangle is 7 yd more than 5 times the width. the perimeter is 150 yd. find the length and the width.

Answer 1

P = 2(L + W)
P = 150
L = 5W + 7

150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width

L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length