Question

A stuntman jumps from the roof of a building to the safety net below. How far has the stuntman fallen after 1.6 seconds?

Answer 1

ok.....

Given,
Time = 1.6 seconds

We know,
initial velocity = 0 m/s²
acceleration (due to gravity) = 9.8 m/s²

Now,
We know,
$s=ut+ \frac{1}{2}at^2\\\\ Substituting \ the \ given\ and\ known\ values,\ we\ get,\\ \\ s=(0)(1.6)+ \frac{1}{2}(9.8)(1.6)^2\\\\Now,\ Using\ the\ calculator\, we\ get,\\\\ s = 0+12.544\\\\s = 12.544\ m$

So, the stuntman has fallen 12.544 meters.

Answer 2

that was a really complicated answer he gave hahaha, just use the kinematic formula (d=vit+1/2at^2)
d=(0x1.6) + ( 0.5x9.8x1.6^2)
d=12.544m